请教各位，'float' object is not subscriptable 的问题出在哪里啊

夺命土豆泥

1. list_001 = [9.1454247, 53.48538079999999, 9.01548, 53.16778, 9.1434819, 53.4873555, 9.1451686, 53.48564990000001, 9.14256, 53.48726, 9.1393, 53.48882, 9.145203, 53.4865261, 9.1449977, 53.4899644, 9.1448787, 53.4857361, 9.14495, 53.48965, 9.145296799999999, 53.485342, 9.1447931, 53.4865513, 9.1454247, 53.48538079999999]
   
2. 
   
3. for num1 in range(1, len(list_001)):
   
4.   k1 = list_001[num1][0]
   
5.   k2 = list_001[num1][1]
   
6.   print(num1)
   
7.   print(k1)
   
8.   print(k2)
   

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运行结果报错是

  File "C:\Python_3.6\Python_File_Py\EX_001\range_print.py", line 4, in <module>
    k1 = list_001[num1][0]
TypeError: 'float' object is not subscriptable

请教大家应该怎么改正啊

我知道答案 回答被采纳将会获得10 C币 已有3人回答

马小朵

1. for num1 in range(len(list_001)):
   
2.   k1 = list_001[num1]
   
3.   k2 = list_001[num1+1]
   
4.   print(num1)
   
5.   print(k1)
   
6.   print(k2)

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高建波师悦未来校园

不知道你想要輸出哪裡一種結果：
以下兩種，有可能其中一種是你要的

1. list_001 = [9.1454247, 53.48538079999999, 9.01548, 53.16778, 9.1434819, 53.4873555, 9.1451686, 53.48564990000001, 9.14256, 53.48726, 9.1393, 53.48882, 9.145203, 53.4865261, 9.1449977, 53.4899644, 9.1448787, 53.4857361, 9.14495, 53.48965, 9.145296799999999, 53.485342, 9.1447931, 53.4865513, 9.1454247, 53.48538079999999]
   
2. 
   
3. for i, num1 in enumerate(list_001):
   
4.     k1 = list_001[i]
   
5.     k2 = list_001[i+1]
   
6.     print(num1)
   
7.     print(k1)
   
8.     print(k2)

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1. list_001 = [9.1454247, 53.48538079999999, 9.01548, 53.16778, 9.1434819, 53.4873555, 9.1451686, 53.48564990000001, 9.14256, 53.48726, 9.1393, 53.48882, 9.145203, 53.4865261, 9.1449977, 53.4899644, 9.1448787, 53.4857361, 9.14495, 53.48965, 9.145296799999999, 53.485342, 9.1447931, 53.4865513, 9.1454247, 53.48538079999999]
   
2. 
   
3. for i in range(0, len(list_001), 2):
   
4.     k1 = list_001[i]
   
5.     k2 = list_001[i+1]
   
6.     print(i)
   
7.     print(k1)
   
8.     print(k2)

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戢宁革

num1在这里是1～25，如果要遍历list_001 直接for num1 in list_001就可以了。如果是要访问第N个元素list_001[N]