4.7. 深入 Python 函数定义

def ask_ok(prompt, retries=4, complaint='Yes or no, please!'):
    while True:
        ok = input(prompt)
        if ok in ('y', 'ye', 'yes'):
            return True
        if ok in ('n', 'no', 'nop', 'nope'):
            return False
        retries = retries - 1
        if retries < 0:
            raise OSError('uncooperative user')
        print(complaint)

i = 5

def f(arg=i):
    print(arg)

i = 6
f()

def f(a, L=[]):
    L.append(a)
    return L

print(f(1))
print(f(2))
print(f(3))

[1]
[1, 2]
[1, 2, 3]

def f(a, L=None):
    if L is None:
        L = []
    L.append(a)
    return L