struct 模块为使用变长的二进制记录格式提供了 pack() 和 unpack() 函数。下面的示例演示了在不使用 zipfile 模块的情况下如何迭代一个 ZIP 文件的头信息。压缩码 和 分别表示2和4字节无符号数字, 表明它们都是标准大小并且按照 little-endian 字节排序。 import struct
with open('myfile.zip', 'rb') as f:
data = f.read()
start = 0
for i in range(3): # show the first 3 file headers
start += 14
fields = struct.unpack('<IIIHH', data[start:start+16])
crc32, comp_size, uncomp_size, filenamesize, extra_size = fields
start += 16
filename = data[start:start+filenamesize]
start += filenamesize
extra = data[start:start+extra_size]
print(filename, hex(crc32), comp_size, uncomp_size)
start += extra_size + comp_size # skip to the next header
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